You want (x,-3) to be on the same straight line as the other two points.
Figure out the equation for that straight line. The slope is [7 - (-5)/[6 - (-2)] = 3/2
The line equation is y = (3/2)x + b
The value of b is given by
7 = (3/2)6 + b = 9 + b
Therefore b = -2 and the line equation is
y = (3/2)x - 2
Now if the point (x,-3) is going to be on that line, we must have
-3 = (3/2)x -2
3/2 x = -1
x = -2/3
find the value of x so (x,-3) is collinear to (6,7) and (-2,-5). Show all work.
2 answers
OR
their slopes have to be equal
(-3-7)/(x-6) = (-5-7)/(-2-6)
-10/(x-6) = -12/-8
-12x + 72 = 80
-12x = 8
x = -8/12 = -2/3
their slopes have to be equal
(-3-7)/(x-6) = (-5-7)/(-2-6)
-10/(x-6) = -12/-8
-12x + 72 = 80
-12x = 8
x = -8/12 = -2/3