Find the value of x given that

Question

Log(15-5x)-1 log(3x-2)

Answer 1

Seems incomplete. Should there be an equals sign somewhere?

Also, if you could post your work for your questions, that would help us help you.

Answer 2

assuming that you meant
log(15-5x)-1 = log(3x-2)
then recall that log10 = 1, so that's the same as
log ((15-5x)/10) = log (3x-2)
if the logs are the same, so are the numbers:
(15-5x)/10 = 3x-2
and you can finish it up.

Answer 3

Log(15-5x) - 1 = Log(3x-2).
Log(15-5x) - Log(3x-2) = 1,
Recall that Log A - Log B = Log(A/B)
Log((15-5x)/(3x-2)) = 1, Log10 = 1
Therefore, (15-5x)/(3x-2) = 10,
15-5x = 30x-20,
X =

Answer 4

X=1