1000(1+.0155/4)^20-1/(.0155)
careful with brackets, secondly you already did .062/4 , so why are you dividing .0155 by 4 ??
amount = 1000 ( 1.0155^20 - 1)/.0155
= 1000( 23.237857...)
= $ 23237.86
Find the value of the ordinary annuity at the end of the indicated time period. The payment R, frequency of deposits m (which is the same as the frequency of compounding), annual interest rate r, and time period t are given.
amount 1,000; quarterly; 6.2%, five years
How do I solve this?
First I took r/m=.062/4=.0155
Then I took T=5 years and times it by 4 (compound quarterly) =20
Then I entered
1000(1+.0155/4)^20-1/(.0155)
What do I do from here?
Thanks!
1 answer