(√(x+4)-2)/x
using l'Hospital's Rule, that gives
(1/(2√(x+4)))/(1) = (1/(2*2))/2 = 1/4
Find the value of the limit.
lim �ã(x+4) - 2 divided by x
x->0
The 2 is outside of the square root.
The answer is supposed to be 1/4 but I keep getting 0/0 no matter how many times I redo the algebra.
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