Find the value of the function y=3x ^2 −21 when x=4 .(1 point)

Answer 1

To find the value of the function when x=4, we can substitute x=4 into the function and evaluate:

y = 3(4^2) - 21

First, we calculate 4^2:

4^2 = 16

Next, we calculate 3(16):

3(16) = 48

Finally, we subtract 21 from 48:

48 - 21 = 27

Therefore, when x=4, the value of the function y = 3x^2 - 21 is 27.