you do it by converting it to int[x/x^(3/2)+2/x^(3/2)]= int[1/x^(1/2)+2/x^(3/2)]=
int[x^(-1/2)+2*x^(-3/2)]=
[2x^(1/2)-4*x^(-1/2)]x=16...25=
10-4/5-8+1=
11/5
Find the value of the definite integral:
int= integral sign
int((x + 2)/(x^(3/2)),x= 16..25)dx
I have no idea how to start this... would I get rid of the fraction?
2 answers
Oops, I should have been more specific. I need to solve it using sums, not antiderivates.