Find the value of K so that x^2-5x+k=0 has one root equal to 4.
3 answers
No idea
Recall that for
x^2+bx+c
the product of the roots is c.
If the other root is m, then
4m = k
4+m = 5
Looks like m=1, so k=4
x^2-5x+4 = (x-4)(x-1)
x^2+bx+c
the product of the roots is c.
If the other root is m, then
4m = k
4+m = 5
Looks like m=1, so k=4
x^2-5x+4 = (x-4)(x-1)
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