Find the value of K so that the point P lies on the line L.

Question

1. P(2,1), L: 3x + Ky = 8

2. P(2,2), L: Kx + (K + 1)y = 2

Help me i have no idea how to do this! :[

Answer 1

in your given point, the first number is the x value, the second number is the y value.
So just substitute.
3(2) + k(1) = 8
6 + k = 8
k = 2

Do the second one the same way, let me know what you got.

Answer 2

Is this right?

k(2) + 2 = -k(2) + 2
4k = 0
k = 0

Answer 3

Your last two lines are correct, but how did you get your first line from the given equation

My line would have been

k(2) + (k+1)(2) = 2
then
2k + 2k + 2 = 2
leading to your last two lines.