Find the value of c which satisfies Mean Value Theorem for the function f(x)=sin(x) on the closed interval (-3ð/2,3ð/2).

Answer 1

y = sin x
y' = cos x

I guess that is -3 pi/2 to + 3 pi/2
sin 3 pi/2 = -1
sin -3 pi/2 = 1

-1 - 1 = -2

-1/(3 pi) = -.1061

cos^-1 -.1061 = 96.1 degrees
= 1.677 radians
cos is odd function so also -1.677 radians