find the value...
lim (tan 2x- x)/(3x- sin x)
x>0
2 answers
plz answer without L hospital rule
using the well-known proofs that sinx -> x, we can conclude that
tan2x -> 2x
so we have the limit as
(2x-x)/(3x-x) = 1/2
tan2x -> 2x
so we have the limit as
(2x-x)/(3x-x) = 1/2