Find the value for W when the limit as x approaches 8 of ((2x^2)-7x + W)/(x-8) = 25

Answer 1

apparently we want w to be such that

2x^2 - 7x + w

is divisible by x-8, so when we divide the only undefined point is the hole at x=9.

So, we have (x-8)(2x-k)

when x=8, we need 2x-k=25, so, k=-9

(x-8)(2x+9) = x^2 -7x - 72
so, w = -72