find the v of an object that has fallen 92 ft round to the nearest 100th

Answer 1

To find the final velocity of an object that has fallen 92 ft, we can use the kinematic equation for free fall:

v^2 = u^2 + 2as

Where:
v = final velocity
u = initial velocity (assumed to be 0 for an object in free fall)
a = acceleration due to gravity (32 ft/s^2)
s = distance fallen (92 ft)

Plugging in the values, we get:

v^2 = 0 + 2 * 32 * 92
v^2 = 5888
v ≈ √5888
v ≈ 76.72 ft/s

Therefore, the final velocity of the object that has fallen 92 ft is approximately 76.72 ft/s.