Start with a number AB which is 10A+B
and the reverse is 10B+A
using the information in the question
3(10A+B)-4(10B+A)=8
26A-37B=8
Now neither A or B can be zero (0A or 0B is not a valid number)
also we can say that if B>=A then the result is negative.
We can from the equation infer that A is only slightly larger than B
So I tred
A=5 B=3
A=6 B=4
A=7 B=5
Find the two digit number such that if you treble it and you take away four times the reverse of that number, the ansswer will be 8.
1 answer