Find the total area enclosed by the curves
y= absolute value of x; y=x^2–2
4 answers
Dr WLS already gave you quite a hint in your typo below.
OK, it looks like the question you submitted just before this was incorrectly stated, as I expected.
See my response to your previous question, where one of the functions was x^2 +2. Integrate x - x^2 +2 from 0 to 2, and double the result. This will take advantage of symmetry of the enclosed zone about the y axis.
See my response to your previous question, where one of the functions was x^2 +2. Integrate x - x^2 +2 from 0 to 2, and double the result. This will take advantage of symmetry of the enclosed zone about the y axis.
how come they will integrate from 0 to 2 and not -1 to 2? that is what i got when i made the two equations equal to find where they intersect
They intersect at -2 and +2. The areas on opposite sides of the y axis are equal, so you can double the area of one side, from x = 0 to 2.