Find the torque on the meter stick for each situation. Ignore the mass of the meter stick. At 1/2 meter there is a 1000g weight. At 1 meter on the same stick there is a 500g weight. What is the torque? Not understanding how to come up with this answer. Keep getting it wrong.
5 answers
Torque about what point? One end? The center?
I don't understand your question, however here are other parts of the same question and the answers are correct.
All on the same 1 meter stick. Assuming g=10m/s/s:
500g weight on the right end of the stick; torque = 5 Nm.
750g weight on the right end of the stick; torque = 7.5 Nm
500g weight at the 1/2 way point on the stick; torque = 2.5 Nm.
All on the same 1 meter stick. Assuming g=10m/s/s:
500g weight on the right end of the stick; torque = 5 Nm.
750g weight on the right end of the stick; torque = 7.5 Nm
500g weight at the 1/2 way point on the stick; torque = 2.5 Nm.
Ok, that is measureing torque about the free end.
So on your,
Torque=force*distance+force*distance
Torque=1kg*10N/kg*.5m + .5kg*10N/kg*1m
= 5Nm+5Nm=10Nm
Now note: 10m/s^2=10N/kg, which is easier to use in these, you are looking for force*distance
So on your,
Torque=force*distance+force*distance
Torque=1kg*10N/kg*.5m + .5kg*10N/kg*1m
= 5Nm+5Nm=10Nm
Now note: 10m/s^2=10N/kg, which is easier to use in these, you are looking for force*distance
Thanks much. This is what I needed to understand.
angular momentum of a system of particles