find the tension in an elevator cable which must support a 4000 N elevator with a maximum upward acceleration of 2 g's. What would be the tension if the elevator were allowed to accelerate downward at .25g's?

Answer 1

Upwards:
-ma = mg –T1,
T1 = m(g+a).
Downwards:
ma = mg –T2,
T2 =m(g-a).