The surface area of a cylinder can be found by adding together the area of the circular top and bottom and the area of the curved side.
The area of each circular base is $\pi r^2$, where $r$ is the radius. In this case, the radius is $13/2 = 6.5$ inches, so each circular base has an area of $(6.5)^2 \pi = 42.25 \pi$ square inches.
The area of the curved side is the height times the circumference of the base. In this case, the height is 14 inches, and the circumference of each circular base is $2\pi r = 13\pi$ inches. So the area of the curved side is $14\cdot 13\pi = 182\pi$ square inches.
Adding up all three areas, we get a total surface area of $2(42.25\pi) + 182\pi = 266.5\pi$. To the nearest whole number, this is $\boxed{837}$ square inches.
Find the surface area of the cylinder to the nearest whole number. The figure is not drawn to scale. 13in, 14in
A: 7,433
B: 2,205
C: 1,144
D: 1,062
1 answer
1 answer