To find the surface area of the cylinder, we can use the formula S.A. = 2πrh + 2πr^2.
Substituting in the given values, we have S.A. = 2π(4)(6) + 2π(4)^2.
Simplifying, we get S.A. = 48π + 32π.
To round to the nearest tenth, we need to approximate π to a decimal value. Using 3.14 as an approximation for π, we get S.A. ≈ 48(3.14) + 32(3.14).
Calculating, we have S.A. ≈ 150.72 + 100.48.
Adding these together, we get S.A. ≈ 251.2.
Therefore, the surface area of the cylinder is approximately 251.2 m^2. Rounded to the nearest tenth, this is 251.3 m^2.
So the answer is 251.3 m^2.
Find the surface area of the cylinder. S.Α. = 2πrh+2πr^2 Round to the nearest tenth.
r = 4 m
h = 6 m
80 m^2
251.3 m^2
301.4 m^2
401.9 m^2
1 answer
1 answer