Find the surface area of a textbook that is 2 in. × 14 in. × 9 in.

1. 172 in.2
2. 50 in.2
3. 344 in.2
4. 252 in.2

1 answer

To find the surface area of a rectangular prism (which a textbook is modeled as), we use the formula for the surface area \( S \):

\[ S = 2(lw + lh + wh) \]

where \( l \) is the length, \( w \) is the width, and \( h \) is the height.

In this case, the dimensions of the textbook are:

  • Length \( l = 2 , \text{in} \)
  • Width \( w = 14 , \text{in} \)
  • Height \( h = 9 , \text{in} \)

Now, we will calculate each of the areas of the three different pairs of sides:

  1. \( lw = 2 , \text{in} \times 14 , \text{in} = 28 , \text{in}^2 \)
  2. \( lh = 2 , \text{in} \times 9 , \text{in} = 18 , \text{in}^2 \)
  3. \( wh = 14 , \text{in} \times 9 , \text{in} = 126 , \text{in}^2 \)

Now we will plug these values into the surface area formula:

\[ S = 2(28 + 18 + 126) \]

Calculating the sum inside the parentheses:

\[ 28 + 18 + 126 = 172 \]

Now, multiply by 2:

\[ S = 2 \times 172 = 344 , \text{in}^2 \]

Thus, the surface area of the textbook is \( \boxed{344 , \text{in}^2} \).

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