To find the surface area of a rectangular prism (which a textbook is), you can use the formula:
\[ \text{Surface Area} = 2(lw + lh + wh) \]
where \( l \), \( w \), and \( h \) are the length, width, and height of the prism, respectively. In this case, the dimensions are:
- \( l = 2 , \text{in} \)
- \( w = 14 , \text{in} \)
- \( h = 9 , \text{in} \)
Now, let's calculate each term inside the parentheses:
- \( lw = 2 \times 14 = 28 , \text{in}^2 \)
- \( lh = 2 \times 9 = 18 , \text{in}^2 \)
- \( wh = 14 \times 9 = 126 , \text{in}^2 \)
Now, we sum these areas:
\[ lw + lh + wh = 28 + 18 + 126 = 172 , \text{in}^2 \]
Now, plug this sum into the surface area formula:
\[ \text{Surface Area} = 2(172) = 344 , \text{in}^2 \]
Thus, the surface area of the textbook is \( 344 , \text{in}^2 \).
The correct response is 344 in.² (or 344 in²).