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Find the surface area of a tetrahedron that has edges the length of 12 centimeters.
4 answers
the surface area of a rectangular prism is 190 square inches, the length is 10 inches, and the width is 3 inches. Find the height
A regular tetrahedron has edges of length 5cm.
Calculate: the surface area of a tetrahedron with edge length of 10cm.
Calculate: the surface area of a tetrahedron with edge length of 10cm.
The surface area of a regular tetrahedron with edges of length "a" is given by the formula:
Surface Area = √3a^2
So, when the edge length is 5cm,
Surface Area = √3(5cm)^2 = √3(25cm^2) = 25√3 cm^2
When the edge length is 10cm,
Surface Area = √3(10cm)^2 = √3(100cm^2) = 100√3 cm^2
Therefore, the surface area of the tetrahedron with edges of length 10cm is 100√3 cm^2.
Surface Area = √3a^2
So, when the edge length is 5cm,
Surface Area = √3(5cm)^2 = √3(25cm^2) = 25√3 cm^2
When the edge length is 10cm,
Surface Area = √3(10cm)^2 = √3(100cm^2) = 100√3 cm^2
Therefore, the surface area of the tetrahedron with edges of length 10cm is 100√3 cm^2.
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