To find the surface area of a rectangular pyramid, we need to find the areas of each of the five faces and then sum them up.
The base of the pyramid is a rectangle with dimensions 15m by 12m, so its area is 15m * 12m = 180m^2.
The four triangular faces of the pyramid are congruent, so we only need to find the area of one of them. Each triangular face has a base that is equal to the width of the rectangle (12m) and a height that is equal to the height of the pyramid (10m). The area of one triangular face is (12m * 10m) / 2 = 60m^2.
Since there are four triangular faces, their combined area is 4 * 60m^2 = 240m^2.
To find the total surface area, we add the area of the base to the combined area of the four triangular faces:
180m^2 + 240m^2 = 420m^2.
Therefore, the surface area of the rectangular pyramid is 420 square meters.
Find the surface area of a rectangular pyramid with these measurements: l = 15 m, w = 12 m, and h = 10 m. Express your answer as a decimal rounded to the nearest hundredth
1 answer