To find the surface area of a rectangular pyramid, we need to calculate the area of each face and then add them together.
The rectangular pyramid has a length (l) of 8 yd, a width (w) of 4 yd, and a height (h) of 2 yd.
The base of the pyramid is a rectangle with dimensions 8 yd. (length) and 4 yd. (width), so the area of the base is 8 yd. x 4 yd. = 32 yd^2.
Next, we need to find the area of the four triangular faces. The formula for the area of a triangle is 1/2 * base * height.
For the triangular faces, the base is the length or width of the base rectangle, which is 8 yd. So, the base of each triangle is 8 yd.
The height of each triangular face is the height of the pyramid, which is 2 yd.
Therefore, the area of each triangular face is 1/2 * 8 yd. * 2 yd. = 8 yd. * 2 yd. = 16 yd^2.
Since there are four triangular faces, the total area of the triangular faces is 4 * 16 yd^2 = 64 yd^2.
Finally, we add the area of the base and the area of the triangular faces together to get the total surface area of the rectangular pyramid.
Total surface area = base area + area of triangular faces
Total surface area = 32 yd^2 + 64 yd^2 = 96 yd^2
Therefore, the correct answer is 96 yd^2.
Find the surface area of a rectangular pyramid with these measurements: l
= 8 yd., w = 4 yd., and h
= 2 yd.(1 point)
Responses
43.31 yd.2
43.31 yd. 2
66 yd.2
66 yd. 2
55.55 yd.2
55.55 yd. 2
72.52 yd.2
1 answer