find the surface area of a rectangular pyramid with these measurements: l=8 yd., w=4 yd., and h=2 yd. (1 point)

Answer 1

To find the surface area of the rectangular pyramid, we need to find the areas of each of its faces and then add them together.

The rectangular pyramid has 5 faces: the base and 4 triangular faces.

To find the area of the base, we multiply the length and width of the base. So, the area of the base is 8 yd. * 4 yd. = 32 sq. yd.

To find the area of each triangular face, we can use the formula for the area of a triangle: (1/2) * base * height.

The base of each triangular face is the same as one side of the base, which is 8 yd.
The height of each triangular face is the height of the pyramid, which is 2 yd.

So, the area of each triangular face is (1/2) * 8 yd. * 2 yd. = 8 sq. yd.

Since there are 4 triangular faces, the total area of the triangular faces is 4 * 8 sq. yd. = 32 sq. yd.

Finally, to find the surface area of the pyramid, we add the area of the base and the area of the triangular faces: 32 sq. yd. + 32 sq. yd. = 64 sq. yd.

Therefore, the surface area of the rectangular pyramid is 64 sq. yd.