To find the surface area of a rectangular pyramid, we need to calculate the area of the base and the areas of the four triangular faces.
The area of the base is lw, so with l = 8 yd. and w = 4 yd., the area of the base is 8 * 4 = 32 yd^2.
Each triangular face of the pyramid has a base of length l and a height of h. So, each triangular face has an area of 0.5 * l * h = 0.5 * 8 * 2 = 8 yd^2.
Since there are four triangular faces, the total area of the triangular faces is 4 * 8 = 32 yd^2.
Therefore, the surface area of the rectangular pyramid is the sum of the area of the base and the area of the triangular faces, which is 32 + 32 = 64 yd^2.
So, the correct answer is 64 yd.2
Find the surface area of a rectangular pyramid with these measurements: l = 8 yd., w = 4 yd., and h = 2 yd.(1 point) Responses 66 yd.2 66 yd. 2 55.55 yd.2 55.55 yd. 2 72.52 yd.2 72.52 yd. 2 43.31 yd.2
1 answer