To find the surface area of a rectangular pyramid, we need to find the sum of the areas of all its faces.
The base of the pyramid is a rectangle with length 13 cm and width 11 cm, so the area of the base is 13 cm * 11 cm = 143 cm^2.
Each of the four triangular faces has a base that is one of the sides of the rectangle and a height equal to the height of the pyramid. The area of each triangle is 1/2 * l * h.
Therefore, the area of one of the triangular faces is 1/2 * 13 cm * 8 cm = 52 cm^2.
Since there are four triangular faces, the total area of the triangular faces is 4 * 52 cm^2 = 208 cm^2.
The total surface area of the rectangular pyramid is the sum of the area of the base and the area of the triangular faces, which is 143 cm^2 + 208 cm^2 = 351 cm^2.
Therefore, the surface area of this rectangular pyramid with the given measurements is 351 cm^2.
Find the surface area of a rectangular pyramid with these measurements: l = 13 cm, w = 11 cm, and h = 8 cm. Express your answer as a decimal rounded to the nearest hundredth.(1 point)
cm2
3 answers
wrong again. The base of the pyramid is not square, so the area is
13*11 + 2(1/2 * 11*8) + 2(1/2 * 13*8) = 335 cm^2
13*11 + 2(1/2 * 11*8) + 2(1/2 * 13*8) = 335 cm^2
You are correct, I apologize for the mistake in my previous response.
The base of the pyramid is a rectangle with length 13 cm and width 11 cm, so the area of the base is 13 cm * 11 cm = 143 cm^2.
Each of the four triangular faces has a base that is one of the sides of the rectangle and a height equal to the height of the pyramid. The area of each triangle is 1/2 * base * height.
Therefore, the area of one of the triangular faces is 1/2 * 11 cm * 8 cm = 44 cm^2.
Since there are four triangular faces, the total area of the triangular faces is 4 * 44 cm^2 = 176 cm^2.
The total surface area of the rectangular pyramid is the sum of the area of the base and the area of the triangular faces, which is 143 cm^2 + 176 cm^2 = 319 cm^2.
Therefore, the correct surface area of this rectangular pyramid with the given measurements is 319 cm^2.
The base of the pyramid is a rectangle with length 13 cm and width 11 cm, so the area of the base is 13 cm * 11 cm = 143 cm^2.
Each of the four triangular faces has a base that is one of the sides of the rectangle and a height equal to the height of the pyramid. The area of each triangle is 1/2 * base * height.
Therefore, the area of one of the triangular faces is 1/2 * 11 cm * 8 cm = 44 cm^2.
Since there are four triangular faces, the total area of the triangular faces is 4 * 44 cm^2 = 176 cm^2.
The total surface area of the rectangular pyramid is the sum of the area of the base and the area of the triangular faces, which is 143 cm^2 + 176 cm^2 = 319 cm^2.
Therefore, the correct surface area of this rectangular pyramid with the given measurements is 319 cm^2.
11 answers