To find the surface area of a rectangular pyramid, we need to calculate the area of each face and then sum them up.
The base of the pyramid is a rectangle with dimensions I = 14m and w = 10m. The area of the base is given by A = I * w.
A = 14m * 10m = 140m^2
Now, let's calculate the area of the four triangular faces. Each face is a right triangle, and we have the height (h = 15m) and one side (I = 14m) of each triangle.
The formula to find the area of a right triangle is A = (1/2) * base * height.
The area of each triangular face can be calculated as follows:
Face 1: A = (1/2) * 14m * 15m = 105m^2
Face 2: A = (1/2) * 14m * 15m = 105m^2
Face 3: A = (1/2) * 10m * 15m = 75m^2
Face 4: A = (1/2) * 10m * 15m = 75m^2
Now we can sum up the areas of all the faces:
Total surface area = 140m^2 + 105m^2 + 105m^2 + 75m^2 + 75m^2 = 500m^2.
Rounding to the nearest hundredth, the surface area of the rectangular pyramid is 500.0m^2.
find the surface area of a rectangular pyramid with these measurements I=14m, w=10m, and h=15 round your answer to nearest hundredth keep in mind you have the height not the slant height
respones 526.89m 500.0m 531.81m 504.93m
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