Find the surface area of a rectangular pyramid with these measurements l =8 cm, w = 4 cm, and h = 2 cm express your answer as a decimal rounded to the nearest hundredth.

Answer 1

To find the surface area of a rectangular pyramid, we need to find the area of each face and add them together.

The base of the pyramid is a rectangle with length (l) and width (w). The area of the base is lw.

The lateral faces are triangle-shaped. Each lateral face has a base with length (l) and height (h), so the area of each lateral face is (1/2)lh.

The total surface area is:

lw + (1/2)lh + (1/2)lh + (1/2)lh

Substituting the given values:

8 cm * 4 cm + (1/2) * 8 cm * 2 cm + (1/2) * 8 cm * 2 cm + (1/2) * 8 cm * 2 cm

32 cm² + 8 cm² + 8 cm² + 8 cm²

56 cm²

Rounding to the nearest hundredth, the surface area of the rectangular pyramid is approximately 56.00 cm².

Answer 2

wrong

Answer 3

I apologize for the mistake.

To find the surface area of a rectangular pyramid, we need to find the area of each face and add them together.

The base of the pyramid is a rectangle with length (l) and width (w). The area of the base is lw.

The lateral faces are triangle-shaped. Each lateral face has a base with length (l) and height (h), so the area of each lateral face is (1/2)lh.

The total surface area is:

lw + 2*(1/2)lh

Substituting the given values:

8 cm * 4 cm + 2*(1/2) * 8 cm * 2 cm

32 cm² + 2*(1/2) * 8 cm * 2 cm

32 cm² + 2*8 cm²

32 cm² + 16 cm²

48 cm²

Rounding to the nearest hundredth, the surface area of the rectangular pyramid is approximately 48.00 cm².