Ask a New Question
Search
Find the surface area formed by revolving the graph of f(x)=81-x^2 on the interval [0,9] about the y-axis. (express the answer in terms of pie.)
Similar Questions
R is the region bounded above by the graph of f(x)=2e^−x^2 and below by the x-axis over the interval [1,2]. Find the volume of
2 answers
Let R be the region in the first quadrant that is enclosed by the graph of y = tanx, the x-axis, and the line x = π/3
h. Find
1 answer
find the volume generated by revolving the area bounded by y=-x^3, y=0, and x=-2 about the line x=1.
I know how to the solve the
1 answer
Find the volume formed by revolving about line 𝑥 = 1 the area bounded by the curve 𝑦 = (𝑥2 −1)2 and the x-axis.
0 answers
more similar questions