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Find the sum to infinity of the geometric series n=1 ,3/10n =3/10+3/1000+....................

1 answer

do you simply have

3/10 + 3/1000 + 3/100000 + ..

a = 3/10 or .3
r = 1/100 or .01

sum(∞) = a/(1-r) = .3/.99 = 30/99 = 10/33
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