do you simply have
3/10 + 3/1000 + 3/100000 + ..
a = 3/10 or .3
r = 1/100 or .01
sum(∞) = a/(1-r) = .3/.99 = 30/99 = 10/33
Find the sum to infinity of the geometric series n=1 ,3/10n =3/10+3/1000+....................
1 answer