find the sum of the series: sum from k=1 to infinity [(3/k(k+1)(k+2))+(-2/3)^k]
2 answers
i know that for 3/k(k+1)(k+2) I would use partial fraction representation
and the (-2/3)^k part is just a geometric series
S = (-2/3)/(1+2/3) = -2/5
S = (-2/3)/(1+2/3) = -2/5