find the sum of the infinite geometric series
1/3+1/9+1/27
sum=a_1/1-r
2 answers
please help me.
well, clearly
a_1 = 1/3
and r = 1/3
so just plug in your values:
S = a/(1-r) = (1/3)/(1 - 1/3) = 1/2
a_1 = 1/3
and r = 1/3
so just plug in your values:
S = a/(1-r) = (1/3)/(1 - 1/3) = 1/2
2 answers