Find the sum of the first eight terms of an arithmetic progression whose first term is 6and whose last term is 46

Answer 1

To find the sum of the first eight terms of an arithmetic progression, we can use the formula:

Sum = n/2 * (first term + last term)

Given that the first term is 6 and the last term is 46, we can plug in the values:

Sum = 8/2 * (6 + 46)
Sum = 4 * 52
Sum = 208

Therefore, the sum of the first eight terms of the arithmetic progression is 208.