Find the sum of the first eight terms of a linear sequence whose first term is 6 and last term is 46

Answer 1

is 46 the 8th term?

Answer 2

If 46 is the 8th term, then
S8 = 8/2 (6+46) = 208

Answer 3

Is 208 the final answer?

Answer 4

sn=n/2(2a+<n-1>d)

Answer 5

tn=a+(n-1)d
T8=6+(8-1)d
46=6+(8-1)d
46=6+7d
7d=46-6
7d=40
d=40/7
d=5.7
sn=n/2(2a+<n-1>d)
=8/2(2times6(8-1)5.7)
=4(12+(39.9)
=4times51.9
=204