Find the sum of the first eight terms of a linear sequence whose first term is 6 and whose last term is 46

6 answers

Sn = n/2 (A1+An)
= 8/2 (6+46)
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IS IT 208
S/n =n/2[A+D]
A=6
D=46
8/2 [6+46]
4[52]
208