Find the sum of the first eight terms of a linear sequence whose first term is 6 and whose last term is 46

Answer 1

Sn = n/2 (A1+An)
= 8/2 (6+46)

Answer 2

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Answer 3

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Answer 4

Good

Answer 5

IS IT 208

Answer 6

S/n =n/2[A+D]
A=6
D=46
8/2 [6+46]
4[52]
208