Find the sum of the first 40 terms of the arithmetic sequence. 19, 24, 29, 34
2 answers
dude why do you put su hard question on here and nobody can do it
In wikipedia type
"Arithmetic progression"
you wil find everythink about Arithmetic progression
Sn=sum of numbers
Sn=(n/2)*[2a1+(n-1)*d]
In this case:
n=40
a1=19
d=5
S40=(40/2)*[2*19+(40-1)*5]=20*(38+39*5)=20*(38+195)=20*233=4660
"Arithmetic progression"
you wil find everythink about Arithmetic progression
Sn=sum of numbers
Sn=(n/2)*[2a1+(n-1)*d]
In this case:
n=40
a1=19
d=5
S40=(40/2)*[2*19+(40-1)*5]=20*(38+39*5)=20*(38+195)=20*233=4660
1 answer