find the sum of the first 24 terms of the arithmetic sequence, if the first term is 3 and the commom difference is 3.
2 answers
Isnt there a formula for this? http://www.algebralab.org/lessons/lesson.aspx?file=Algebra_ArithSeries.xml
sum(n) = n/2[2a + (n-1)d)
sum(24) = 12[6 + 23(3)]
= ....
sum(24) = 12[6 + 23(3)]
= ....