Find the sum and reduce to lowest terms. (1 point) Responses Image with alt text: start fraction 12 over 8 end fraction Image with alt text: start fraction 12 over 16 end fraction Image with alt text: start fraction 3 over 4 end fraction

1 answer

To find the sum of the given fractions and reduce it to lowest terms, we need to first identify the fractions from the images you mentioned. However, since I can't see the images, I will assume the fractions you provided based on your description:

  1. \( \frac{12}{8} \)
  2. \( \frac{12}{16} \)
  3. \( \frac{3}{4} \)

Let's add them:

  1. First, simplify each fraction:
  • \( \frac{12}{8} = \frac{3}{2} \) (dividing both the numerator and denominator by 4)
  • \( \frac{12}{16} = \frac{3}{4} \) (dividing both the numerator and denominator by 4)

Now, we sum these fractions. The least common denominator (LCD) of \( \frac{3}{2} \) and \( \frac{3}{4} \) is 4.

  1. Convert \( \frac{3}{2} \) to have the denominator of 4:

\[ \frac{3}{2} = \frac{3 \times 2}{2 \times 2} = \frac{6}{4} \]

  1. Now we can add:

\[ \frac{6}{4} + \frac{3}{4} = \frac{6 + 3}{4} = \frac{9}{4} \]

  1. The last fraction \( \frac{3}{4} \) is also already in the same form, and we have now calculated the sum as:

\[ \frac{9}{4} + \frac{3}{4} = \frac{12}{4} = 3 \]

The final sum, reduced to lowest terms, is \( 3 \).

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