Find the strain and stress on a 1.5 inch diameter cylinder which is subjected to a load of 7.8 tons and measures 11.92 inches instead of the original 12 inch length. What is the Modulus of Elasticity for the material?

Answer 1

7.8 tons is 15,600 lb.
Divide than by the area in square inches (pi*0.75^2) for the stress in p.s.i.

The modulus of elasticity is (stress)/(strain)

The strain, which is dimensionless, is 0.08/12 = 6.67*10^-3

I hope that helps.