Find the standard form of the equation of the parabola with the given characteristics.

Vertex: (-9, 8); directrix: x = -16

3 answers

plug and chug
(y-k)^2 = 4a (x-h)
k = 8 given
h = -9 given
distance from vertex to directrix = a
distance from -9 to - 16 = 7 = a (positive for directrix to the left of the vertex)
so
(y-8)^2 = 28 (x+9)
Focus: ​(1515​,00​)​; ​ Directrix: xequals=negative 15
Focus: ​(15,0​)​; ​ Directrix: x= -15