find the standard deviation for each data set use the standard deviations to compare the pair of data sets fastest recored speeds of various large wild cats (mph)

Question

60 50 25 45 45 40 25 35 15
fasted recorded speeds of various birds in flight (mph)
216 105 98 53 63 35 50 30 50 25 25 30
the standard deviation of the large wild cats is o=
round the final answer to the nearest 100th as needed

Answer 1

Standard deviation for fastest recorded speeds of large wild cats:

1. Calculate the mean:
(60 + 50 + 25 + 45 + 45 + 40 + 25 + 35 + 15) / 9 = 36.11

2. Calculate the squared differences from the mean:
(60-36.11)^2 = 577.92
(50-36.11)^2 = 192.69
(25-36.11)^2 = 123.38
(45-36.11)^2 = 78.83
(45-36.11)^2 = 78.83
(40-36.11)^2 = 14.75
(25-36.11)^2 = 123.38
(35-36.11)^2 = 1.35
(15-36.11)^2 = 446.02

3. Calculate the variance:
(577.92 + 192.69 + 123.38 + 78.83 + 78.83 + 14.75 + 123.38 + 1.35 + 446.02) / 9 = 158.40

4. Calculate the standard deviation:
sqrt(158.40) = 12.59 mph

The standard deviation of the fastest recorded speeds of large wild cats is approximately 12.59 mph.