Find the square root of the following by prime factorization 7056

Answer 1

7056 = 2 * 3528 = 2^2 * 1714 = 2^3 * 857

Now factor 857. You know there are no more 2's in there, so start with 3, and so on.

So, what do you get? Since there are only three 2's, the square root will not be an integer, but will have a radical left over.

Answer 2

7056 = (2*2*2*2)*(3*3)*(7*7)
= 16*9*49

so √7056 = 4*3*7 = 84

Answer 3

I see I can neither factor nor count. Go with Reiny.