oh, yeah? Too bad you didn't show your work...
substitute #2 into #1 and you have
-2x+2 = 2x^2 - 2x - 3
2x^2 - 5 = 0
x = ±√(5/2)
I suspect a typo, but this is the way to do it.
Find the solution to the system
y = 2x2 - 2x - 3
y = -2x + 2
A) (-1,1) and (1, -3)
B) (0, -1) and (-0.5, 0)
C) (0.5, -3.5) and (0, -3)
D) (2, 1) and (0,0)
Can someone please help me I tried doing it and I did not come out with anyone of these answers.
2 answers
That is what I did but none of those r the answers.