To find the solution set of the inequalities \(4x - 3 > 9\) and \(x + 6 > -2\), we will solve each inequality separately.
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Solving the first inequality: \[ 4x - 3 > 9 \] Add 3 to both sides: \[ 4x > 12 \] Divide by 4: \[ x > 3 \]
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Solving the second inequality: \[ x + 6 > -2 \] Subtract 6 from both sides: \[ x > -8 \]
Now, we need to find the values of \(x\) that satisfy both inequalities \(x > 3\) and \(x > -8\). The more restrictive condition here is \(x > 3\).
Thus, the solution set is: \[ {x \mid x > 3} \]
Therefore, the answer is: \[ {x \mid x > 3} \]