OK. Now you show me yours, and I'll show you mine.
Just clear the fraction and get rid of the parens. Then it's clear sailing.
Find the solution set
2x + [3x-(4x-5) ]=x/4-2
a.28/3
b.-28/3
c.9
d.-9
4 answers
2x+3x-4x+5=x/2
x-5=x/2
-5=x/2-x
i don't know what next ,,,
x-5=x/2
-5=x/2-x
i don't know what next ,,,
you must multiply everything by 4 to clear the fraction. Why did you continue on with another fraction? And your arithmetic is wrong, as well.
2x + [3x-(4x-5) ]=x/4-2
8x + 4[3x-(4x-5) ] = x-8
8x + 12x - 16x + 20 = x - 8
4x+20 = x-8
3x = -28
x = -28/3
2x + [3x-(4x-5) ]=x/4-2
8x + 4[3x-(4x-5) ] = x-8
8x + 12x - 16x + 20 = x - 8
4x+20 = x-8
3x = -28
x = -28/3
ok i get this tnx mr steve
1 answer