Assuming the usual sloppiness with parentheses, I parse you equation as
(x-1)/(x^2-9) + 1/(x-3) = 2/(x+3)
using a common denominator of (x+3)(x-3), we have
(x-1) + 1(x+3) - 2(x-3)
-------------------------- = 0
(x-3)(x+3)
assuming x is not 3 or -3, that leaves us with
x-1+x+3-2x+6 = 0
8 = 0
Looks like no solution.
Find the solution of the given equations.
x-1/x^2-9+1/x-3=2/x+3
Thank you! :)
1 answer