y = 2√x
y' = 1/√x
so at the point (a,2√a) the tangent line has equation
y-2√a = 1/√a (x-a)
so plug in whatever numbers you like
Find the slope of the tangent to the curve y=2sqrt(x) at the point where x=a.
Find equations of the tangent lines at the points (1, 2) and (9, 6).
1 answer