Find the slope of the tangent line to the graph y = x^-3 at the point (0.5, 8).

Question

-48

-12

4

16

Answer 1

y'=-3/x^2 = -3(4)

Answer 2

The derivative should have been
dy/dx = -3x^-4
= -3/x^4

when x = .5 or 1/2
dy/dx = -3/(1/2)^4
= -3/(1/16
= -3(16)
= -48