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Find the slope of the tangent line to the graph of the given function at the given value of x.

y=-5x^1/2+x^3/2; x=25

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just evaluate f'(x) at x=25

f'(x) = -5/2 x^(-1/2) + 3/2 x^(1/2)
= (-5/2)(1/5) + 3/2 (5)
= 7

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