The slope of the tangent for any x is
f'(x) = 2x-1
So, you want the line
y-f(3) = f'(3) * (x-3)
Find the slope of the tangent line and the equation of the tangent line to f(x)=x^2-x at x=3
3 answers
We weren't allowed to just use derivatives for it we had to do this using limits. That's why I was unsure of this.
I guarantee that your text has this very problem in it. It starts out as the limit of
√(x+h)-√x
------------
h
That's hard to handle, but if you multiply top and bottom by √(x+h)+√x things will drop out nicely when you take the limit.
√(x+h)-√x
------------
h
That's hard to handle, but if you multiply top and bottom by √(x+h)+√x things will drop out nicely when you take the limit.